What is this function, $f(x) = \frac{1}{\exp(-kx)+1}$, where $k$ is a constant, called?
$\endgroup$ 11 Answer
$\begingroup$It's a special case of the logistic function.
$\endgroup$What is this function, $f(x) = \frac{1}{\exp(-kx)+1}$, where $k$ is a constant, called?
$\endgroup$ 1It's a special case of the logistic function.
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