Is ${1\over 1}+{1\over 2}+{1\over 3}+\cdots +{1\over n}$ computable? I couldn't find any formulas to find the result. The explanation would be very helpful. Thanks before.
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$\begingroup$I think what you are looking for is the harmonic number.
$\endgroup$ 2 $\begingroup$Yes. The result is: $$S=\Psi(n+1)+\gamma$$ where:$$S=\sum_{k=1}^n \frac{1}{k}$$ For the explanation see:
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