I can't do problems such as $ \displaystyle \csc \theta - \sin \theta = \frac{\cos^2 \theta}{\sin \theta}$
Because I simply do not know how to deal with the 'subtraction' component involved. I don't even know how to subtract trigonometric fractions from each other. Can someone help here with respect to the question?
$\endgroup$ 52 Answers
$\begingroup$Hint: Finding a common denominator goes something like this: $\frac{1}{b} - a = \frac{1}{b} - \frac{ab}{b} = \frac{1-ab}{b}$ and $\csc{\theta} = \frac{1}{\sin{\theta}}$
$\endgroup$ $\begingroup$$\csc\theta - \sin\theta$
$=\frac{1}{\sin\theta} - \sin\theta$
$=\frac{1}{\sin \theta} - \frac{\sin^2 \theta}{\sin\theta}$
$=\frac{1-\sin^2 \theta}{\sin\theta}$
$=\frac{\cos^2 \theta}{\sin\theta}$
$\endgroup$