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$\begingroup$ Please explain and help. Thank you in advance
$\endgroup$ 3 1 Answer
$\begingroup$ Using Vieta's formulas, we have:
$$
\begin{eqnarray}
a+b &=& -\frac{-3}{2} = \frac{3}{2}\\
ab &=& \frac{-6}{2} = -3
\end{eqnarray}
$$
So:
$$
\begin{eqnarray}
(a+2)(b+2) &=& ab + 2a + 2b + 4\\
&=& ab + 2(a+b) + 4\\
&=& -3 + 2(\frac{3}{2}) + 4\\
&=& 4
\end{eqnarray}
$$
$\endgroup$ 
