Starting with the graph of $f(x) = 3^x$, write the equation of the graph that results from reflecting $f(x)$ about the line $x=3$.
I thought that it would be $f(x) = 3^{-x-3}$ (aka shift it three units to the right and reflect it), but it's wrong.
The right answer is $f(x) = 3^{-x+6}$ but I just can't get to it!
An explained step by step would be appreciated so I can follow what is being done.
Thanks in advance!
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$\begingroup$Your idea will work if you just carry it fully through. First shift three units to the left, so the line of reflection becomes the y axis, then flip, and finally remember to shift three units back to the right to put the center line back where it belongs.
(This gives the $f(6-x)$ solution you already know).
$\endgroup$ 2 $\begingroup$Replace $x$ with $6-x$. This works because if $x=3+t$, then $6-x=3-t$.
Or, in words: if $x$ is $t$ units to the right from $3$, then $6-x$ is $t$ units to the left from $3$.
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