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A cubic graph for $x^3 + 4x^2 + 2x - 4$ is given.
Question is: Find an equation of the line you would draw on that graph to solve graphically: $x^3 + 4x^2 + 3x - 1 = 0.$
Give the answer in $y = mx + c$ form.
$\endgroup$ 31 Answer
$\begingroup$$x^3 + 4x^2 + 3x - 1 = 0$ $\Leftrightarrow$ $x^3 + 4x^2 + 2x - 4 =-x-3 $
Then answer is $y=-x-3$.
Solutions of $x^3 + 4x^2 + 3x - 1 = 0$ is intersection points$$x\approx0.247,\quad x\approx-1.445,\quad x\approx-2.802$$
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