I made this script exif_scriptAnd want to change ep variable to double digit Eg 01 instread of 1.
#!/bin/bash
x=0
ep=1
while [ $x -le 11 ]
do echo "Welcome $x times" date --date="$x week" +"%Y:%m:%d" exiftool -exififd:dateTimeOriginal="$(date --date="$x week" +"%Y:%m:%d") 00" $1$ep* x=$(( $x + 1 )) ep=$(( $ep + 1 ))
done 6 3 Answers
You can use shell parameter expansion to add zero-padding to numbers.
For example, to print number in a 5-digits format:
$ zeroos="00000"
$ number="123"
$ temp_num="$zeroos$number"
$ echo "${temp_num:(-5)}"
00123
# Or instead of the "5" constant, use $zeroos length
$ echo "${temp_num:(-${#zeroos})}"
00123Update:
Above example cuts off the front-most digits of $number, when the number becomes longer (with more digits) than $zeroos:
$ number="1234567" # Changed to 7 digits
echo "${temp_num:(-5)}"
34567 # Resulted in a wrong number!A safer way:
$ number="123"
$ echo "${zeroos:${#number}:${#zeroos}}${number}"
00123
$ number="1234567"
$ echo "${zeroos:${#number}:${#zeroos}}${number}"
1234567Note 1:
A slightly different variant, to use the first digits of $zeroos resp. $century (instead of the last ones) would be:
$ century="2000"
$ year="1"
$ echo "${century:0:-${#year}}${year}"
2001This comes in handy for example, if you have mixed dates with 1-, 2- or even 4-digit years, but want them to be 4 digits in any case, without the need of conditions (for checking their actual digits) and any arithmetic.
The downside is, if ${#year} gets greater than ${#century}, this results in an error.
Note 2:
When using printf (as suggested on other answers), be aware that it could be mush slower on a large scale (see an example).
1Using your script, the following will work.
#!/bin/bash
x=0
ep=1
while [ $x -le 11 ]
do ep_padded=$(printf '%02d' $ep) echo "Welcome $x times" date --date="$x week" +"%Y:%m:%d" exiftool -exififd:dateTimeOriginal="$(date --date="$x week" +"%Y:%m:%d") 00" $1$ep_padded* x=$(( $x + 1 )) ep=$(( $ep + 1 ))
doneYou can use the following form to increment your variables too
x=$((++x))
ep=$((++ep)) 5 set your variable as below, this will add a padding zero, you can add more zeros in case of your expectations.
ep="$(printf '%02d' $((++ep)) )" 3